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Zsh completion argument type coercion
Why does this not work?
case $argv in
*-e)
echo You entered “$argv”
;;
*-f)
echo You entered “$argv”
;;
*)
;;
esac
If i enter -e or -f with argument then i would expect the echo to be executed:
-e test
-f test
But it isn’t? It’s like i “try” to enter -e or -f but not enter them
A:
The shell is indeed having its way with your argument, but it’s really not losing arguments (at least not by design). The shell sees -e test or -f test as 3 distinct arguments. It’s smart enough to know that the two that look like arguments are not actually arguments, so it skips them. The one that looks like an argument is a literal argument, so it applies to that one. It is case sensitive, so -e is passed to the -e case branch and test to the * case branch.
From the manual:
If only one component of the list is present in the $PATH, only that
component is searched.
In short, if you want to do some kind of logic on the arguments, you are better off constructing a new command (i.e., not using case as a form of string comparisons, because this is something that will require jumping through some hoops to emulate.
export.registerModule(‘eventBus’, (exports) => {
const botConfig = require(‘../../../../frontend/assets/js/botConfig.js’);
const http
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